Individual Problem
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Some examples of student work |
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Back side of student work, shows work, working backwards with formula of area and circumference. |
6.5 Surface Area of a Cylinder
Thursday, January 14 - Monday, January 18
Homework: Homework and practice book p.132-133 #1-4
Textbook Assessment Focus Question p. 260 #6
Homework: Homework and practice book p.132-133 #1-4
Textbook Assessment Focus Question p. 260 #6
Goal:
We will be able to calculate the surface area of a cylinder using the given formula:
SA= 2πr² + 2πrh
To solve surface area for cylinder above:
SA = 2πr² + 2πrh
= 2 x 3.14 x 3² + 2 x 3.14 x 3 x 5
= 2 x 3.14 x 9 + 3.14 x 3 x 5
= 56.52 + 47.1
= 2662.09 cm ²
SA = 2πr² + 2πrh
= 2 x 3.14 x 3² + 2 x 3.14 x 3 x 5
= 2 x 3.14 x 9 + 3.14 x 3 x 5
= 56.52 + 47.1
= 2662.09 cm ²
Scavenger Hunt:
Students were given clues to lead the to hidden questions around the room. Questions were based on volume and surface area. Congrats TEAMCAP for winning 1st place! Other winning teams were also given table bonus points.
6.4 Volume of a Cylinder
Tuesday, January 12 - Wednesday, January 13Homework: Popcorn Activity
Goal:
We will be able to calculate the volume of a cylinder using the given formula:
V = π r²h (Volume = pi multiplied by the radius squared multiplied by height) OR
V = π r x r x h (Volume = pi multiplied by radius multiplied by radius multiplied by height)
Refer to the above video for directions on how to solve problems with the given formula.
6.3 Area of a Circle
Friday, January 8 - Monday, January 11
Homework: Practice and Homework Book pgs 128-129 #1-6
Homework: Practice and Homework Book pgs 128-129 #1-6
Goal:
We will be able to calculate the area of a circle using the given formula:
A = π r² (Area = pi multiplied by the radius squared) or written
A = π r x r (Area = pi multiplied by radius multiplied by radius)
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Students were asked to make the note that Area: the number of square units inside the circle. We always write our answer for area in units². In this case, it is cm². |
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Some class problem solving |
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Some class problem solving |
6.2 Circumference
Wednesday, January 6 - Thursday, January 7
Homework: Practice and Homework Book pg. 125 #1-5
and
Math Text Book pg. 245 #6, 7, 8, and 11 A only
Goals:
We will understand π = 3.14
We will be able to calculate the circumference (distance around the circle) using the given formulas
C = π x d (Circumference = pi multiplied by diameter) or
C = π x 2r (Circumference = pi multiplied by two times the radius)
We will be able to calculate the circumference (distance around the circle) using the given formulas
C = π x d (Circumference = pi multiplied by diameter) or
C = π x 2r (Circumference = pi multiplied by two times the radius)
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We measured the distance around circular objects and found their diameter and radius |
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Circumference Note for Concept Book. |
6.1 Investigating Circles - Radius and Diameter
Monday, January 4 - Tuesday January 5Homework: Practice and Homework Book pg. 123 #1-6
Goal: We will be able to calculate the radius and diameter of circles using the given formulas.
R= D/2 (Radius = Diameter divided by 2)
and
D = 2r (Diameter= Radius multiplied by 2)
R= D/2 (Radius = Diameter divided by 2)
and
D = 2r (Diameter= Radius multiplied by 2)
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Definitions we will be using for the circles unit. |
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How to calculate radius and diameter using the formulas. |
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Steps to constructing a circle. Then we did some questions as a class to calculate radius and diameter. |
Some practice:
Students were asked to find the center of the logo and radius and diameter of the logo they were given. They were asked to place the logo in the center of the t-shirt. Some measuring or folding of the shirt was required. On the back of the shirts, students were asked to show their work.
More practice:

Students, in their table groups, we given one plate. They were given the problem which asked, "How many plates would you be able to fit over the entire surface of the desk?"
Which meant that they had to find the length/width of the plate (the diameter) and divide that number by the length and width they measured of their desks.
Those two new numbers can be multiplied to find the answer.
Which meant that they had to find the length/width of the plate (the diameter) and divide that number by the length and width they measured of their desks.
Those two new numbers can be multiplied to find the answer.
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